Problem:

x^2-w^2

over

x^3-w^3

times

x^2+xw+w^2

over

x^2+2xw+w^2

Soooes....

How would I even begin this? O-o Should I try to factor them first, or should I go straight to multiplication? I know x^2+2xw+w^2 factors into (x+w)(x+w), but the top portion doesn't factor at all.

x^2-w^2 is a difference of two squares, so it becomes (x-w)(x+w)

And x^3-x^3 is a difference of two cubes, so it becomes (x-w)(x^2+xw+w^2)

Doesn't it?

so then...we're essentially left with:

(x-w)(x+w)(x^2+xw+w^2)

over

(x-w)(x^2+xw+w^2)(x+w)(x+w)

And, once you eliminate, you're left with...

O_o 0?

I'm not sure my math is right there...O-o..I was thinking I would be left with (x-w) over (x+w)